8x^2-10x+11=36

Solution for 8x^2-10x+11=36 equation:

8x^2-10x+11=36

We move all terms to the left:

8x^2-10x+11-(36)=0

We add all the numbers together, and all the variables

8x^2-10x-25=0

a = 8; b = -10; c = -25;
Δ = b2-4ac
Δ = -102-4·8·(-25)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-30}{2*8}=\frac{-20}{16}
=-1+1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+30}{2*8}=\frac{40}{16}
=2+1/2
$